Mathematical relationship between the voltage input to a clock and its BPM

Good evening, community. My neurons have melted, and I can’t seem to find the mathematical relationship between the BPM of a clock (in this case, CLKD from Impromptu) and the voltage applied to the BPM/CV input. What I’m certain of is that it’s not linear, as indicated by the graph from the following values: -1.977 V > 30 BPM / -1.012 V > 60 BPM / 0 V > 120 BPM / 1 V > 240 BPM and 1.323 V > 300 BPM. I’m sure this relationship is in the module code, but I’m not expert enough to find it… Could someone help me?

I expect it is exponential in theory as with frequency/Hz.

(Herz is phase or “beats” per second)

30 bpm = 0.5 Hz, 60 bpm = 1Hz, 120 bpm = 2Hz Etc Etc

So it follows an oct (or doubling of bpm) per Volt.

Correct me if I am wrong :slightly_smiling_face:

^^^ This agrees with the documentation Voltage Standards - VCV Rack Manual

Thank you very much for these very clear answers. It also helped me realize that a clock is nothing more or less than an oscillator delivering rectangular signals.( My neurons are really tired!)

2 Likes